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An SQL JOIN
clause combines records from two or more tables in a database. It creates a set that can be saved as a table or used as is. A JOIN
is a means for combining fields from two tables by using values common to each. ANSI standard SQL specifies four types of JOIN
s: INNER
, OUTER
, LEFT
, and RIGHT
. In special cases, a table (base table, view, or joined table) can JOIN
to itself in a self-join.
A programmer writes a JOIN
predicate to identify the records for joining. If the evaluated predicate is true the combined record is then produced in the expected format, for example a record set or a temporary table.
Sample tables
All subsequent explanations on join types in this article make use of the following two tables. The rows in these tables serve to illustrate the effect of different types of joins and join-predicates. In the following tables, Department.DepartmentID
is the primary key, while Employee.DepartmentID
is a foreign key.
LastName | DepartmentID |
---|---|
Rafferty | 31 |
Jones | 33 |
Steinberg | 33 |
Robinson | 34 |
Smith | 34 |
Jasper | NULL |
DepartmentID | DepartmentName |
---|---|
31 | Sales |
33 | Engineering |
34 | Clerical |
35 | Marketing |
Note: The "Marketing" Department currently has no listed employees. Also, employee "Jasper" has not been assigned to any Department yet.
Inner join
An inner join creates a new result table by combining column values of two tables (A and B) based upon the join-predicate. The query compares each row of A with each row of B to find all pairs of rows which satisfy the join-predicate. When the join-predicate is satisfied, column values for each matched pair of rows of A and B are combined into a result row. The result of the join can be defined as the outcome of first taking the Cartesian product (or cross-join) of all records in the tables (combining every record in table A with every record in table B) - then return all records which satisfy the join predicate. Actual SQL implementations normally use other approaches where possible, since computing the Cartesian product is very inefficient. The inner join is the most common join operation used in applications, and represents the default join-type.
SQL specifies two different syntactical ways to express joins. The first, called "explicit join notation", uses the keyword JOIN
, whereas the second uses the "implicit join notation". The implicit join notation lists the tables for joining in the FROM
clause of a SELECT
statement, using commas to separate them. Thus, it specifies a cross-join, and the WHERE
clause may apply additional filter-predicates. Those filter-predicates function comparably to join-predicates in the explicit notation.
One can further classify inner joins as equi-joins, as natural joins, or as cross-joins (see below).
Programmers should take special care when joining tables on columns that can contain NULL values, since NULL will never match any other value (or even NULL itself), unless the join condition explicitly uses the IS NULL
or IS NOT NULL
predicates.
As an example, the following query joins the Employee and Department tables using the DepartmentID column of both tables. Where the DepartmentID of these tables match (i.e. the join-predicate is satisfied), the query will combine the LastName, DepartmentID and DepartmentName columns from the two tables into a result row. Where the DepartmentID does not match, no result row is generated.
Example of an explicit inner join:
SELECT * FROM employee INNER JOIN department ON employee.DepartmentID = department.DepartmentID
is equivalent to:
SELECT * FROM employee, department WHERE employee.DepartmentID = department.DepartmentID
Explicit Inner join result:
Employee.LastName | Employee.DepartmentID | Department.DepartmentName | Department.DepartmentID |
---|---|---|---|
Robinson | 34 | Clerical | 34 |
Jones | 33 | Engineering | 33 |
Smith | 34 | Clerical | 34 |
Steinberg | 33 | Engineering | 33 |
Rafferty | 31 | Sales | 31 |
Notice that the employee "Jasper" and the department "Marketing" does not appear. Neither of these has any matching records in the respective other table: "Jasper" has no associated department and no employee has the department ID 35. Thus, no information on Jasper or on Marketing appears in the joined table. Depending on the desired results, this behavior may be a subtle bug. Outer joins may be used to avoid it.
Equi-join
An equi-join, also known as an equijoin, is a specific type of comparator-based join, or theta join, that uses only equality comparisons in the join-predicate. Using other comparison operators (such as <
) disqualifies a join as an equi-join. The query shown above has already provided an example of an equi-join:
SELECT * FROM employee INNER JOIN department ON employee.DepartmentID = department.DepartmentID
SQL provides an optional shorthand notation for expressing equi-joins, by way of the USING
construct (Feature ID F402):
SELECT * FROM employee INNER JOIN department USING (DepartmentID)
The USING
construct is more than mere syntactic sugar, however, since the result set differs from the result set of the version with the explicit predicate. Specifically, any columns mentioned in the USING
list will appear only once, with an unqualified name, rather than once for each table in the join. In the above case, there will be a single DepartmentID
column and no employee.DepartmentID
or department.DepartmentID
.
The USING
clause is supported by MySQL, Oracle, PostgreSQL, SQLite, and DB2/400.
Natural join
A natural join offers a further specialization of equi-joins. The join predicate arises implicitly by comparing all columns in both tables that have the same column-name in the joined tables. The resulting joined table contains only one column for each pair of equally-named columns.
The above sample query for inner joins can be expressed as a natural join in the following way:
SELECT * FROM employee NATURAL JOIN department
As with the explicit USING
clause, only one DepartmentID column occurs in the joined table, with no qualifier:
DepartmentID | Employee.LastName | Department.DepartmentName |
---|---|---|
34 | Smith | Clerical |
33 | Jones | Engineering |
34 | Robinson | Clerical |
33 | Steinberg | Engineering |
31 | Rafferty | Sales |
With either a JOIN USING
or NATURAL JOIN
, the Oracle database implementation of SQL will report a compile-time error if one of the equijoined columns is specified with a table name qualifier: "ORA-25154: column part of USING clause cannot have qualifier" or "ORA-25155: column used in NATURAL join cannot have qualifier", respectively.
Cross join
A cross join, cartesian join or product provides the foundation upon which all types of inner joins operate. A cross join returns the cartesian product of the sets of records from the two joined tables. Thus, it equates to an inner join where the join-condition always evaluates to True or where the join-condition is absent from the statement.
If A and B are two sets, then the cross join is written as A × B.
The SQL code for a cross join lists the tables for joining (FROM
), but does not include any filtering join-predicate.
Example of an explicit cross join:
SELECT * FROM employee CROSS JOIN department
Example of an implicit cross join:
SELECT * FROM employee, department;
Employee.LastName | Employee.DepartmentID | Department.DepartmentName | Department.DepartmentID |
---|---|---|---|
Rafferty | 31 | Sales | 31 |
Jones | 33 | Sales | 31 |
Steinberg | 33 | Sales | 31 |
Smith | 34 | Sales | 31 |
Robinson | 34 | Sales | 31 |
Jasper | NULL | Sales | 31 |
Rafferty | 31 | Engineering | 33 |
Jones | 33 | Engineering | 33 |
Steinberg | 33 | Engineering | 33 |
Smith | 34 | Engineering | 33 |
Robinson | 34 | Engineering | 33 |
Jasper | NULL | Engineering | 33 |
Rafferty | 31 | Clerical | 34 |
Jones | 33 | Clerical | 34 |
Steinberg | 33 | Clerical | 34 |
Smith | 34 | Clerical | 34 |
Robinson | 34 | Clerical | 34 |
Jasper | NULL | Clerical | 34 |
Rafferty | 31 | Marketing | 35 |
Jones | 33 | Marketing | 35 |
Steinberg | 33 | Marketing | 35 |
Smith | 34 | Marketing | 35 |
Robinson | 34 | Marketing | 35 |
Jasper | NULL | Marketing | 35 |
The cross join does not apply any predicate to filter records from the joined table. Programmers can further filter the results of a cross join by using a WHERE
clause.
Outer joins
An outer join does not require each record in the two joined tables to have a matching record. The joined table retains each record—even if no other matching record exists. Outer joins subdivide further into left outer joins, right outer joins, and full outer joins, depending on which table(s) one retains the rows from (left, right, or both).
(In this case left and right refer to the two sides of the JOIN
keyword.)
No implicit join-notation for outer joins exists in standard SQL.
Left outer join
The result of a left outer join (or simply left join) for table A and B always contains all records of the "left" table (A), even if the join-condition does not find any matching record in the "right" table (B). This means that if the ON
clause matches 0 (zero) records in B, the join will still return a row in the result—but with NULL in each column from B. This means that a left outer join returns all the values from the left table, plus matched values from the right table (or NULL in case of no matching join predicate). If the left table returns one row and the right table returns more than one matching row for it, the values in the left table will be repeated for each distinct row on the right table.
For example, this allows us to find an employee's department, but still shows the employee(s) even when their department does not exist (contrary to the inner-join example above, where employees in non-existent departments are excluded from the result).
Example of a left outer join, with the additional result row italicized:
SELECT * FROM employee LEFT OUTER JOIN department ON employee.DepartmentID = department.DepartmentID
Employee.LastName | Employee.DepartmentID | Department.DepartmentName | Department.DepartmentID |
---|---|---|---|
Jones | 33 | Engineering | 33 |
Rafferty | 31 | Sales | 31 |
Robinson | 34 | Clerical | 34 |
Smith | 34 | Clerical | 34 |
Jasper | NULL | NULL | NULL |
Steinberg | 33 | Engineering | 33 |
Right outer joins
A right outer join (or right join) closely resembles a left outer join, except with the treatment of the tables reversed. Every row from the "right" table (B) will appear in the joined table at least once. If no matching row from the "left" table (A) exists, NULL will appear in columns from A for those records that have no match in A.
A right outer join returns all the values from the right table and matched values from the left table (NULL in case of no matching join predicate).
For example, this allows us to find each employee and his or her department, but still show departments that have no employees.
Example right outer join, with the additional result row italicized:
SELECT * FROM employee RIGHT OUTER JOIN department ON employee.DepartmentID = department.DepartmentID
Employee.LastName | Employee.DepartmentID | Department.DepartmentName | Department.DepartmentID |
---|---|---|---|
Smith | 34 | Clerical | 34 |
Jones | 33 | Engineering | 33 |
Robinson | 34 | Clerical | 34 |
Steinberg | 33 | Engineering | 33 |
Rafferty | 31 | Sales | 31 |
NULL | NULL | Marketing | 35 |
In practice, explicit right outer joins are rarely used, since they can always be replaced with left outer joins (with the table order switched) and provide no additional functionality. The result above is produced also with a left outer join:
SELECT * FROM department LEFT OUTER JOIN employee ON employee.DepartmentID = department.DepartmentID
Full outer join
A full outer join combines the results of both left and right outer joins. The joined table will contain all records from both tables, and fill in NULLs for missing matches on either side.
For example, this allows us to see each employee who is in a department and each department that has an employee, but also see each employee who is not part of a department and each department which doesn't have an employee.
Example full outer join:
SELECT * FROM employee FULL OUTER JOIN department ON employee.DepartmentID = department.DepartmentID
Employee.LastName | Employee.DepartmentID | Department.DepartmentName | Department.DepartmentID |
---|---|---|---|
Smith | 34 | Clerical | 34 |
Jones | 33 | Engineering | 33 |
Robinson | 34 | Clerical | 34 |
Jasper | NULL | NULL | NULL |
Steinberg | 33 | Engineering | 33 |
Rafferty | 31 | Sales | 31 |
NULL | NULL | Marketing | 35 |
Some database systems (like MySQL) do not support this functionality directly, but they can emulate it through the use of left and right outer joins and unions. The same example can appear as follows:
SELECT * FROM employee LEFT JOIN department ON employee.DepartmentID = department.DepartmentID UNION SELECT * FROM employee RIGHT JOIN department ON employee.DepartmentID = department.DepartmentID WHERE employee.DepartmentID IS NULL
SQLite does not support right join, so outer join can be emulated as follows:
SELECT employee.*, department.* FROM employee LEFT JOIN department ON employee.DepartmentID = department.DepartmentID UNION SELECT employee.*, department.* FROM department LEFT JOIN employee ON employee.DepartmentID = department.DepartmentID WHERE employee.DepartmentID IS NULL
Self-join
A self-join is joining a table to itself.[1] This is best illustrated by the following example.
Example
A query to find all pairings of two employees in the same country is desired. If you had two separate tables for employees and a query which requested employees in the first table having the same country as employees in the second table, you could use a normal join operation to find the answer table. However, all the employee information is contained within a single large table. [2]
Considering a modified Employee
table such as the following:
EmployeeID | LastName | Country | DepartmentID |
---|---|---|---|
123 | Rafferty | Australia | 31 |
124 | Jones | Australia | 33 |
145 | Steinberg | Australia | 33 |
201 | Robinson | United States | 34 |
305 | Smith | United Kingdom | 34 |
306 | Jasper | United Kingdom | NULL |
An example solution query could be as follows:
SELECT F.EmployeeID, F.LastName, S.EmployeeID, S.LastName, F.Country FROM Employee F, Employee S WHERE F.Country = S.Country AND F.EmployeeID < S.EmployeeID ORDER BY F.EmployeeID, S.EmployeeID;
Which results in the following table being generated.
EmployeeID | LastName | EmployeeID | LastName | Country |
---|---|---|---|---|
123 | Rafferty | 124 | Jones | Australia |
123 | Rafferty | 145 | Steinberg | Australia |
124 | Jones | 145 | Steinberg | Australia |
305 | Smith | 306 | Jasper | United Kingdom |
For this example, note that:
F
andS
are aliases for the first and second copies of the employee table.- The condition
F.Country = S.Country
excludes pairings between employees in different countries. The example question only wanted pairs of employees in the same country. - The condition
F.EmployeeID < S.EmployeeID
excludes pairings where theEmployeeID
s are the same. F.EmployeeID < S.EmployeeID
also excludes duplicate pairings. Without it only the following less useful part of the table would be generated (for the United Kingdom only shown):
EmployeeID | LastName | EmployeeID | LastName | Country |
---|---|---|---|---|
305 | Smith | 305 | Smith | United Kingdom |
305 | Smith | 306 | Jasper | United Kingdom |
306 | Jasper | 305 | Smith | United Kingdom |
306 | Jasper | 306 | Jasper | United Kingdom |
Only one of the two middle pairings is needed to satisfy the original question, and the topmost and bottommost are of no interest at all in this example.
Alternatives
The effect of outer joins can also be obtained using correlated subqueries. For example
SELECT employee.LastName, employee.DepartmentID, department.DepartmentName FROM employee LEFT OUTER JOIN department ON employee.DepartmentID = department.DepartmentID
can also be written as
SELECT employee.LastName, employee.DepartmentID, (SELECT department.DepartmentName FROM department WHERE employee.DepartmentID = department.DepartmentID ) FROM employee
Implementation
Much work in database-systems has aimed at efficient implementation of joins, because relational systems commonly call for joins, yet face difficulties in optimising their efficient execution. The problem arises because (inner) joins operate both commutatively and associatively. In practice, this means that the user merely supplies the list of tables for joining and the join conditions to use, and the database system has the task of determining the most efficient way to perform the operation. A query optimizer determines how to execute a query containing joins. A query optimizer has two basic freedoms:
- Join order: Because joins function commutatively and associatively, the order in which the system joins tables does not change the final result-set of the query. However, join-order does have an enormous impact on the cost of the join operation, so choosing the best join order becomes very important.
- Join method: Given two tables and a join condition, multiple algorithms can produce the result-set of the join. Which algorithm runs most efficiently depends on the sizes of the input tables, the number of rows from each table that match the join condition, and the operations required by the rest of the query.
Many join-algorithms treat their inputs differently. One can refer to the inputs to a join as the "outer" and "inner" join operands, or "left" and "right", respectively. In the case of nested loops, for example, the database system will scan the entire inner relation for each row of the outer relation.
One can classify query-plans involving joins as follows:[3]
- left-deep
- using a base table (rather than another join) as the inner operand of each join in the plan
- right-deep
- using a base table as the outer operand of each join in the plan
- bushy
- neither left-deep nor right-deep; both inputs to a join may themselves result from joins
These names derive from the appearance of the query plan if drawn as a tree, with the outer join relation on the left and the inner relation on the right (as convention dictates).
Join algorithms
Three fundamental algorithms exist for performing a join operation.
Nested loops
Use of nested loops produces the simplest join-algorithm. For each tuple in the outer join relation, the system scans the entire inner-join relation and appends any tuples that match the join-condition to the result set. Naturally, this algorithm performs poorly with large join-relations: inner or outer or both. An index on columns in the inner relation in the join-predicate can enhance performance.
The block nested loops (BNL) approach offers a refinement to this technique: for every block in the outer relation, the system scans the entire inner relation. For each match between the current inner tuple and one of the tuples in the current block of the outer relation, the system adds a tuple to the join result-set. This variant means doing more computation for each tuple of the inner relation, but far fewer scans of the inner relation.
Merge join
If both join relations come in order, sorted by the join attribute(s), the system can perform the join trivially, thus:
-
- Consider the current "group" of tuples from the inner relation; a group consists of a set of contiguous tuples in the inner relation with the same value in the join attribute.
- For each matching tuple in the current inner group, add a tuple to the join result. Once the inner group has been exhausted, advance both the inner and outer scans to the next group.
Merge joins offer one reason why many optimizers keep track of the sort order produced by query plan operators—if one or both input relations to a merge join arrives already sorted on the join attribute, the system need not perform an additional sort. Otherwise, the DBMS will need to perform the sort, usually using an external sort to avoid consuming too much memory.
Hash join
A hash join algorithm can only produce equi-joins. The database system pre-forms access to the tables concerned by building hash tables on the join-attributes. The lookup in hash tables operates much faster than through index trees. However, one can compare hashed values only for equality, not for other relationships.
See also
Notes
- ^ Shah 2005, p. 165
- ^ Adapted from Pratt 2005, pp. 115–6
- ^ Yu & Meng 1998, p. 213
References
- Pratt, Phillip J (2005), A Guide To SQL, Seventh Edition, Thomson Course Technology, ISBN 9780619216740
- Shah, Nilesh (2005) [2002], Database Systems Using Oracle - A Simplified Guide to SQL and PL/SQL Second Edition (International Edition ed.), Pearson Education International, ISBN 0131911805
- Yu, Clement T.; Meng, Weiyi (1998), Principles of Database Query Processing for Advanced Applications, Morgan Kaufmann, ISBN 9781558604346, http://books.google.com/books?id=aBHRDhrrehYC, retrieved on 2009-03-03
External links
- SQL SERVER - Introduction to JOINs - Basic of JOINs
- SQL Inner Join with visual explanation
- Sybase ASE 15 Joins
- MySQL 5.0 Joins
- Oracle Joins - Quick Reference
- PostgreSQL Join with Query Explain
- PostgreSQL 8.3 Joins
- Joins in Microsoft SQL Server
- Joins in MaxDB 7.6
- Joins in Oracle 11g
- Various join-algorithm implementations
- A Visual Explanation of SQL Joins
- Another visual explanation of SQL joins, along with some set theory
- SQL join types classified with examples
- An alternative strategy to using FULL OUTER JOIN
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